mikewarot
9 hours ago
Transistors are generally at their lowest static power dissipation if the are either fully on or off. The analog middle is great if you're trying to process continuous values, but then you're going to be forced to use a bias current to hold on in the middle, which is ok if that's the nature of the circuit.
A chip with billions of transistors can't reasonably work if most of them are in the analog mode, it'll just melt to slag, unless you have an amazing cooling system.
Also consider that there is only one threshold between values on a binary system. With a trinary system you would likely have to double the power supply voltage, and thus quadruple the power required just to maintain noise margins.
throw10920
8 hours ago
This is great point, and I'll extend it by claiming that there's a more general physical principle underneath: that it's significantly easier to build bistable systems than tristable (or higher) systems, so much so that it makes up for the fact that you need more of them.
This is far more general than electronic systems (e.g. quantum computers follow the same principle - it's far easier to build and control qubits than qutrits/qudits).
(technically, it's even easier to build systems that have a single stable configuration, but you can't really store information in those, so they're not relevant)
rini17
7 hours ago
It can be solved various ways, not only middle, electricity has negative voltages too. So you can have the third distinct "fully on" state at negative voltage. This isn't practical with silicon semiconductors but might be possible with other technology. The Soviet ternary computer Setun used custom ternary switches.
theamk
5 hours ago
there is nothing special about negative voltages, it's all relative to some point anyway.
With mixed analog/digital circuits for example, it's pretty common to treat exactly same voltages either as -2.5/0/2.5 (relative to midpoint), or as 0/2.5/5 (relative to negative rail).
What matters is having multiple treshold voltages with distinct behaviour. Setun used ferrite transformers which do have multiple thresholds (postive and negative fields) - but modern electronics, including transistors, does not.
pezezin
3 hours ago
It is perfectly viable with silicon. The venerable Fast Ethernet used PAM3, as do USB4 and GDDR7, and Gigabit Ethernet uses PAM5.
mikewarot
2 hours ago
Those are analog systems, and thus you have to handle them with transistors operating in a linear mode, which is why there are dedicated circuits to handle the interface and translate it back into something binary as soon as possible, so that conventional logic can use the data.
Basically, every ethernet card is now a modem.
foxglacier
8 hours ago
Wouldn't you also get data loss using the linear region of transistors? The output would be have some error from the input and it would propagate through the circuit, perhaps eventually reaching on or off where it would be stuck.