Ohmaps: your image montage is a resistor network

78 pointsposted 10 months ago
by occular

33 Comments

bgoated01

10 months ago

So these addition formulas that apply to series and parallel resistors seem more generally to be formulas for finding the new ratio when you have several ratios and want to add them together treating the quantity in the numerator or the denominator as equal for all ratios. Series circuits have the same current for each ratio, and differing voltages, while parallel circuits have the same voltage for each ratio and a different current for each. Similarly for these aspect ratios, where you want the new ratio after adding width or height while setting the other (height or width, respectively) equal.

strken

10 months ago

This is neat!

When I was fresh out of uni, I got asked to build a system to show recommendations to people based on a graph of connections between them. I tried to mentally think about these as a network of resistors, which led me to dimensionality reduction and from there to alternating least squares. Isomorphisms are fun like that: they can help you find techniques when you're stuck on something.

dekhn

10 months ago

btw you can also convert graphs to matrices and use standard matrix techniques. See the methods section of https://www.sciencedirect.com/science/article/pii/S037887330...

strken

10 months ago

Yep! My problem at the time was that I didn't know I needed a matrix, or which operations would be helpful to perform on one, because I didn't know much about the problem I was trying to solve. I ran into a paper about using SVD on networks of resistors to simplify them, which pointed me in the right direction.

femto

10 months ago

If you made the Piet painting from a substrate with constant resistivity, and put wires between each area, you would end up with a working circuit with all the calculated resistances. This then leads to the insight that it doesn't matter how you divide the painting up, its total resistance only depends on its overall size.

thatcat

10 months ago

it's overall path length would be the total resistance of each part added together, but if you configure the network with different parallel elements it will change the total resistance of the circuit. for parallel R1,R2: Rt = 1/ (1/R1 + 1/R2)

femto

10 months ago

But if the resistors are constrained to fill the area of the entire painting everything cancels out, reducing to: R = resistivity * (length of painting) / (width of painting * thickness of conducting paint).

An example: If you have N parallel resistors constrained to fill the painting, their width (and resistance) must go as 1/N. Plug into the formula you gave and the Ns cancel out, leaving Rt constant.

thatcat

10 months ago

i thought the resistors were just the lines on the mondrain painting, my mistake.

ckocagil

10 months ago

Fun fact: a rectangular sheet of resistor with a specific thickness and terminals at both sides has a resistance unit of: ohms per square. Not square meters, just square!

dvh

10 months ago

If you liked this you are gonna like R-2R DAC.

henearkr

10 months ago

Not all possible Piet Mondriaan-like painting would lead to a valid network, though.

For example if you have a centered square with four identical rectangles organized around in a certain way.

Moreover, even for "valid" paintings, a different network would result from rotating it 90 degrees.

user

10 months ago

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OisinMoran

10 months ago

Very fun! I'm always a big of things being viewed as other things—no idea why though!

twwwt

10 months ago

Ok, if the spatial concept of aspect ratio is the equivalent of electrical resistance, and given the analogy in the article of the painting and the resistor network, what is the equivalence of color then? Frequency?

evoke4908

10 months ago

It's not fundamentally related to anything because the choice of color is completely arbitrary. There are no rules that relate color to any configuration of lines unless you choose to impose arbitrary rules.

user

10 months ago

[deleted]

a1o

10 months ago

In the last drawing I noticed the person wrote 2.2k . This is weird for me, for resistors I usually write 2k2 and see others do the same - I also imagine the two red stripes already...

kragen

10 months ago

I write 2.2kΩ, but I'm used to seeing people just write "2.2k" on schematics (because obviously it isn't 2.2kH or 2.2kV, and also it's next to a resistor symbol).

I think the 2k2 thing is maybe one of those young whippersnapper things like nanofarads, or maybe a European thing. I grew up with 0.001μF capacitors, not 1nF capacitors.

adrian_b

10 months ago

Some physically smaller resistors are marked 2k2 instead of 2.2k, because this requires less space for the marking and it also avoids ambiguities that could happen when the decimal point is too small or erased and 2.2k could be misread as 22k.

kragen

10 months ago

Red red red gold takes less space than that; it's only four pixels, though most of us have never seen a resistor marked with spots instead of stripes.

adrian_b

10 months ago

I agree, but for some reason the marking with color stripes or points appears to have gone out of fashion.

Perhaps the colored marking was more expensive or the marking equipment was slower than what is used now.

kragen

10 months ago

I think color codes require less manufacturing precision but more colors.

dekhn

10 months ago

IIUC this is similar to how window layout is computed in systems like qt.

MeteorMarc

10 months ago

The 3k2 resistor in the Mondriaan network should be 300 ohm, because its height is 3.2 times its width.

henearkr

10 months ago

Yes, I too noticed this error!

user

10 months ago

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